Good job, @DGAlexandru! Yes, i will always try to cummulate all informations gathered here into the Wiki as a reference: 
https://mk4-wiki.denkdose.de/en/artikel ... 13a05f00a1
But it's a hell of a work to do for one person, even now where we are more in research phase... and still good headaches from new years eve party 
 
epson_s1d13a05f00a1_qfp5-128_pinout.jpg
Note that the pins are not directly connected with the CPU but over a signal-buffer/level-shifter (to adopt the 5V level from the MAC to the 3.3V level of the EPSON and vice versa), seen in this picutre at (5), (6) and (7):
convers_vfl_mcu-area_explained.jpg
Meantime i managed to identify most of the routines using the framebuffer and it is like i thought before, there is a off-screen framebuffer starting at 0x20217700 area used to draw everything in advance and then it will memcopied over to the visual area at 0x20200000. This is mentioned also in the datasheet 
"Double Buffering/Multi-pages: provides smooth animation and instantaneous screen updates".
I also found the init-sequence of the EPSON in firmware: 
Code: Select all
int lcdctrl_init()
{
  int result; // r0
  MEMORY[0x20000000] = 0x2D3B;
  MEMORY[0x20000002] = 0x402D;
  result = 0;
  MEMORY[0x20000004] = 0;
  MEMORY[0x20000006] = 0;
  MEMORY[0x20000008] = 0;
  MEMORY[0x2000000A] = 3;
  MEMORY[0x2000000C] = 7;
  MEMORY[0x2000000E] = 97;
  MEMORY[0x20000010] = 192;
  MEMORY[0x20000012] = 8;
  MEMORY[0x20000014] = 0;
  MEMORY[0x20000016] = 0;
  MEMORY[0x20000018] = 0;
  MEMORY[0x2000001A] = 0;
  MEMORY[0x2000001C] = 252;
  MEMORY[0x2000001E] = -772;
  MEMORY[0x20000020] = 0;
  MEMORY[0x20000022] = 63;
  MEMORY[0x20000024] = 0;
  MEMORY[0x20000026] = 49;
  MEMORY[0x20000028] = 0;
  MEMORY[0x2000002A] = 91;
  MEMORY[0x2000002C] = 36;
  MEMORY[0x2000002E] = 10;
  MEMORY[0x20000030] = 0;
  MEMORY[0x20000032] = 262;
  MEMORY[0x20000034] = 0;
  MEMORY[0x20000036] = 239;
  MEMORY[0x20000038] = 0;
  MEMORY[0x2000003A] = 16;
  MEMORY[0x2000003C] = 0;
  MEMORY[0x2000003E] = 0;
  MEMORY[0x20000040] = 0;
  MEMORY[0x20000042] = 0;
  MEMORY[0x20000044] = 0;
  MEMORY[0x20000046] = 100;
  MEMORY[0x20000048] = 0;
  MEMORY[0x2000004A] = 0;
  MEMORY[0x2000004C] = 0;
  MEMORY[0x2000004E] = 0;
  MEMORY[0x20000050] = 0;
  MEMORY[0x20000052] = 0;
  MEMORY[0x20000054] = 0;
  MEMORY[0x20000056] = 0;
  MEMORY[0x20000058] = 0;
  MEMORY[0x2000005A] = 0;
  MEMORY[0x2000005C] = 0;
  MEMORY[0x2000005E] = 0;
  MEMORY[0x20000060] = 0;
  MEMORY[0x20000062] = 0;
  MEMORY[0x20000064] = 1;
  MEMORY[0x20000066] = 0;
  MEMORY[0x20000068] = 0;
  MEMORY[0x2000006A] = 0;
  MEMORY[0x2000006C] = 0;
  MEMORY[0x2000006E] = 0;
  MEMORY[0x2000007C] = 0;
  MEMORY[0x2000007E] = 300;
  MEMORY[0x20000080] = 0;
  MEMORY[0x20000082] = 50;
  MEMORY[0x20000084] = 0;
  MEMORY[0x20000086] = 100;
  MEMORY[0x20000088] = 0;
  MEMORY[0x2000008A] = 10;
  MEMORY[0x2000008C] = 0;
  MEMORY[0x2000008E] = 100;
  MEMORY[0x20000090] = 0;
  MEMORY[0x20000092] = 10;
  MEMORY[0x20000094] = 0;
  MEMORY[0x20000096] = 7;
  MEMORY[0x20000098] = 0;
  MEMORY[0x2000009A] = 0;
  MEMORY[0x2000009C] = (unsigned int)&unk_918;
  MEMORY[0x2000009E] = 3593;
  MEMORY[0x200000A0] = 0;
  MEMORY[0x200000A2] = 0;
  MEMORY[0x200000A4] = 0;
  MEMORY[0x200000A6] = 0;
  MEMORY[0x200000A8] = 0;
  MEMORY[0x200000AA] = 0;
  MEMORY[0x200000AC] = 0;
  MEMORY[0x200000AE] = 0;
  MEMORY[0x200000B0] = 0;
  MEMORY[0x200000B2] = 0;
  MEMORY[0x200000B4] = 0;
  MEMORY[0x200000B6] = 0;
  MEMORY[0x200000B8] = 0;
  MEMORY[0x200000BA] = 0;
  MEMORY[0x200000BC] = 0;
  MEMORY[0x200000BE] = 0;
  MEMORY[0x200000C0] = 0;
  MEMORY[0x200000C2] = 0;
  return result;
}
So we now know the this area is at 0x2000 0000 - 0x2000 00C4. I took a memory snapshot of this area using J-Link Mem: 
Code: Select all
Offset(h) 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
00000000  2D 3B 40 2D 00 00 00 00 00 00 00 03 00 07 00 61  -;@-...........a
00000010  00 40 00 08 00 00 00 00 00 00 00 00 00 FC FC FC  .@...........üüü
00000020  00 00 00 3F 00 00 00 31 00 00 00 5B 00 24 00 0A  ...?...1...[.$..
00000030  00 00 01 06 00 00 00 EF 00 00 00 10 00 00 00 00  .......ï........
00000040  00 00 00 00 00 00 00 64 00 00 00 00 00 00 00 00  .......d........
00000050  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
00000060  00 00 00 00 00 01 00 00 00 00 00 00 00 00 00 00  ................
00000070  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
00000080  00 00 00 32 00 00 00 64 00 00 00 0A 00 00 00 00  ...2...d........
00000090  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000A0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000B0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000C0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000D0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000E0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000000F0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
00000100  2D 3B 40 2D 00 00 00 00 00 00 00 03 00 07 00 61  -;@-...........a
00000110  00 40 00 08 00 00 00 00 00 00 00 00 00 FC FC FC  .@...........üüü
00000120  00 00 00 3F 00 00 00 31 00 00 00 5B 00 24 00 0A  ...?...1...[.$..
00000130  00 00 01 06 00 00 00 EF 00 00 00 10 00 00 00 00  .......ï........
00000140  00 00 00 00 00 00 00 64 00 00 00 00 00 00 00 00  .......d........
00000150  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
00000160  00 00 00 00 00 01 00 00 00 00 00 00 00 00 00 00  ................
00000170  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
00000180  00 00 00 32 00 00 00 64 00 00 00 0A 00 00 00 00  ...2...d........
00000190  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000001A0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000001B0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000001C0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
000001D0  00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ................
You can see the it seems to be mirroried every 0x100, so only 8 address-bits are used for the registers.
epson_s1d13a05f00a1_register_overview.jpg
Bits 16-22 of the first 32-bit register at 0x2000 0000 reflects the CNF-STATUS signal pins of the chip: 0x2D3B402D = 0b001011 01 0  
0111011 01000000 001011 01
That means: 01 1 1011 = Generic #1, Big Endian, WAIT# is active low, CLKI to BCLK divide ratio is 1:1
And this lead to the MPU-Connection type:
epson_s1d13a05f00a1_generic1_bigendian_interface.png
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